Question

an object under goes an acceleration of10m/s starting from rest .find the distance traveled in 5 second​

Answer 1

Answer:

5m

Explanation:

explanation is given in the photo

Answer 2

$\dag\:\underline{\sf AnsWer :}$

In the question it is stated that , a object under goes Acceleration (a) of 10 m/s² starting from rest i.e Initial Velocity (u) will be 0 m/s and time Interval (t) is given as 5 second and we are asked to find the distance traveled (s) by the object in 5 second.

• First of all we need to find the final velocity (v) of the object. So, for calculating final velocity (v) we shall use the first kinematical equation of motion :

$:\implies\sf v = u + at$

$:\implies\sf v = 0+ 10 \times 5$

$:\implies \underline{ \boxed{\sf v = 50 \: m/s}}$

• Hence, the final velocity (v) of the object is 50 m/s. Now, by using third kinematical equation of motion we can find the distance traveled by the object.

$\dashrightarrow\:\:\sf v^2 - u^2 = 2as$

$\dashrightarrow\:\:\sf (50)^2 - (0)^2 = 2 \times 10 \times s$

$\dashrightarrow\:\:\sf 2500 = 20 \times s$

$\dashrightarrow\:\:\sf s = \dfrac{2500}{20}$

$\dashrightarrow\:\:\sf s = \dfrac{250}{2}$

$\dashrightarrow\:\: \underline{ \boxed{\sf s = 125 \: m}}$

Hence,the distance traveled by the object is 125 m.