Question

An object undergoes an acceleration of 0.8m/s² starting from rest .find the distance travelled in one second.​

Answer 1

Answer:

Initial velocity = 0 m/s

Acceleration = 8m/s ²

time taken = 1 sec

And we have to find distance ,

so distance will be,

=>S = ut+ ½at ²

=>S = 0 * 1 + ½ *8*1*1

=>S = 4 * 1

=>S = 4

Therefore distance traveled = 4 m

I hope it helps…………….

Answer 2

Given

• Acceleration (a) = 8.0m/s²
• Initial velocity (u) = 0
• Time (t) = 1s

To find

• Distance travelled

Solution

As we know that

→ s = ut + ½ at²{2nd equation of motion}

→ s = 0 × 1 + ½ × 8 × (1)²

→ s = 0 + 4

→ s = 4m

Hence,

• Distance travelled is 4m

Extra Information

• Force = mass × acceleration
• v = u + at {First equation of motion}
• v² = u² + 2as {third equation of motion}
• Pressure = Force/Area