An object undergoes an acceleration of 10 m/s2 Starting from rest, find the distance travelled in 5s.
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this the ur expected answer
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using the 2nd equation of motion S = ut+1/2+at²
S = 0×5 + 1/2 + 10×5²
= 1/2+250
= 1+250×2/2
= 1+500/2
= 501/2
= 25.5metert
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