Question

An object undergoes an acceleration of 10 metre per second square starting from rest find the distance travelled by it in 5 second

Answer 1

u =0m/s

a=10m/s2

USING 2ND EQUATION OF MOTION》~

s=ut+1/2 at2 we get

s = 0×5 +1/2 ×10×5×5

s =125m

Answer 2

Answer:125 m

Explanation

a=10 m/s^2

u=0

t=5 s

Finding distance by using s=ut+1/2at^2

=0×5+1/2×10×5×5

=0+5×5×5

=0+125

=125 m

S =125 m