Physics, asked by maryvimala2224, 6 months ago

an object undergoes an acceleration of 10 metre per second square starting from rest find the distance travelled in 4 seconds​

Answers

Answered by Anonymous
0

Answer:

10 metre

Explanation:

v = u+at           (newton's first law)

 = 0 +10*4

 = 40 ms-1

 = distance travelled = v/t= 40/4

 = 10m

HOPE IT HELPS

Answered by nandellamayank
0

Answer:

80 m

Explanation:

S = ut + 1/2at²

u = Initial velocity

a = Acceleration

t = Time

⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻Solution⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

u = 0

a = 10 m/s²

t = 4 s

=> 0 × 4 × 1/2 × 10 × 4²

=> 5 × 16

S = 80 m

Hope you found this answer helpful, thank you for asking this question

Similar questions