an object undergoes an acceleration of 10 metre per second square starting from rest find the distance travelled in 4 seconds
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Answered by
0
Answer:
10 metre
Explanation:
v = u+at (newton's first law)
= 0 +10*4
= 40 ms-1
= distance travelled = v/t= 40/4
= 10m
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Answered by
0
Answer:
80 m
Explanation:
S = ut + 1/2at²
u = Initial velocity
a = Acceleration
t = Time
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u = 0
a = 10 m/s²
t = 4 s
=> 0 × 4 × 1/2 × 10 × 4²
=> 5 × 16
S = 80 m
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