Question

an object undergoes an acceleration of 10 ms-2 starting from rest. find the distance traveled in 5 seconds. find this question ans plz.
plz help me guys need your help.

Answer 1

Answer:

125m

Explanation:

u=0

s= 1/2 a t^2

1/2 × 10 × 5×5

=125m

hope help you

Answer 2

Given:

acceleration,a = 10m/s-2

Initial velocity ,u = 0

Time taken , t = 5 sec

To Find :

• distance covered

Solution :

By using second equation of motion :

$\boxed{ \boxed{s = ut + \frac{1}{2}a {t}^{2} }}$

$\implies \: s \: = 0 \times 5 + \frac{1}{2} \times 10 \times {5}^{2}$

$\implies \: s \: = 0 + 5 \times 25$

$\boxed{ \boxed\implies \: s = 125m}$