Math, asked by kumaripriyanka86120, 2 months ago

an object undergoes an acceleration of 10 ms-2 starting from rest. find the distance traveled in 5 seconds.
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Answers

Answered by vcstarbornin2004
1

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Answered by faleehamanal
5

Answer:

Acceleration (a) = 10m/s^{2}

initial velocity (u) = 0 m/s

distance (s) =??

time (t) = 5 seconds

s = ut + \frac{1}{2}at^{2}

s = 0(5)  + \frac{1}{2} (10)  (5)^{2}

s = \frac{1}{2} (10) (25)

s = 125 m

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