English, asked by kumaripriyanka86120, 1 month ago

an object undergoes an acceleration of 10 ms-2 starting from rest. find the distance traveled in 5 seconds.
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Answers

Answered by gauridakare931
1

Explanation:

Given,

a=10m/s

2

u=0m/s

t=5sec

From 2nd equation of motion,

S=ut+

2

1

at

2

S=0×5+

2

1

×10×5×5

S=0+125

S=125m

Answered by Anonymous
204

Given:-

  • Initial velocity, u = 0(As the object starts from rest.)
  • Acceleration, a = 10 m/s².
  • Time taken, t = 5 sec

To Find:-

  • Distance travelled by the object, s

Solution: -

\small\underline{\pmb{\sf \:Using \: 3rd \: equation \: of \: motion  :-}}

 : \implies \underline{ \boxed { \pink{{\frak{s = ut + \dfrac{1}{2} at² }}}}}\\

\sf :\implies s = 0 \times 5 + \dfrac{1}{2} \times 10 \times  5 \times  5\\

\sf :\implies s = 5 \times  25\\

 : \implies \underline{ \boxed { \pink{{\frak{s = 125m }}}}}\\

\therefore\:\underline{\textsf{The  distance covered by object  is\:\textbf{125m}}}.\\

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