Question

An object undergoes an acceleration of 10 Ms Starting from rest .Find the distance travelled In 5 second

Answer 1

Distance travelled by the object is 125M(meter).

• We know that the object starts from rest .
• It undergoes continuous acceleration of 10m/s².
• Time travelled is 5 seconds.
• USing the laws of motion second formula

S(distance) = ut + $\frac{1}{2} at^{2}$

where u is initial velocity,t is time travelled and a is acceleration.

• As the object starts from rest it's initial velocity is 0.
• Substituting the known values in the equation we get,

S = (0)×5 + $\frac{1}{2} (10).5^{2}$

S = 0 + 125

S = 125m

Answer 2

Answer:

Distance travelled by the object is 125M(meter).

We know that the object starts from rest .

It undergoes continuous acceleration of 10m/s².

Time travelled is 5 seconds.

USing the laws of motion second formula

S(distance) = ut + \frac{1}{2} at^{2}

2

1

at

2

where u is initial velocity,t is time travelled and a is acceleration.

As the object starts from rest it's initial velocity is 0.

Substituting the known values in the equation we get,

S = (0)×5 + \frac{1}{2} (10).5^{2}

2

1

(10).5

2

S = 0 + 125

S = 125m