An object undergoes an acceleration of 10 ms starting from rest.find the distance travelled in 5s
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1/2 at^2 = (10×5×5) /2 m = 125m
amansinha779:
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hey there
u (initial position) = 0
s = ?
t = 5 s
a (acceleration) = 10m/s
s = ut + 1/2at square
s= 0*5 + 1/2 *10 *5*5
s = 125 m
^_^ distance = 125 m
u (initial position) = 0
s = ?
t = 5 s
a (acceleration) = 10m/s
s = ut + 1/2at square
s= 0*5 + 1/2 *10 *5*5
s = 125 m
^_^ distance = 125 m
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