An object undergoes an acceleration of 10m/s [POWER 2] starting from rest.Find the distance travelled by it in 5secs
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Answer:
s = 125 m
Explanation:
u = 0
a =10 m/s²
t = 5 s.
s = ?
by using 2 nd equation of motion
s = ut + 1/2 at²
s = 0*5 + 1/2 * 10*25
s = 1/2* 250
s = 125
therefore, distance travelled in 5 seconds is 125 m.
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