An object undergoes an acceleration of 4 m/ ms-² square starting from rest.Find the distance covered by the object in 3 seconds.
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use the second equation of motion to find the distance
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Ayush0605:
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here a = 4m/s square
u =0
t = 3sec
s = 1/2at^2 +ut
s = 1/2×4×9 + 0×3 *9 beacuse square of 3 = 9
s = 18 m
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u =0
t = 3sec
s = 1/2at^2 +ut
s = 1/2×4×9 + 0×3 *9 beacuse square of 3 = 9
s = 18 m
mark me as brainlist please
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