an object undergoes an acceleration of 8m/s^2 starting from rest.find the distance travelled in one second.
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Answered by
4
INITIAL SPEED=0
FINAL VELOCITY=?
TIME TAKEN BE=1 sec
THEREFORE ACCELERATION=
8=V-U/T
8=V
THEREFORE FINAL VELOCITY =8m/s
DISTANCE TRAVELLED= 4 mtrs
USING FORMULA ut+1/2at SQUARE
FINAL VELOCITY=?
TIME TAKEN BE=1 sec
THEREFORE ACCELERATION=
8=V-U/T
8=V
THEREFORE FINAL VELOCITY =8m/s
DISTANCE TRAVELLED= 4 mtrs
USING FORMULA ut+1/2at SQUARE
Answered by
2
u=0
a=8m/s
t=1
s=ut+1/2at^2
=4m
a=8m/s
t=1
s=ut+1/2at^2
=4m
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