An object undergoes an acceleration of 8m/s '2 starting from rest .find the distance travelled in 1 second
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Answered by
12
a =8 m/s²
u =0 m/s
Now, s = ut +1/2at²
= 0×1 + 1/2×8×1²
=4
So, Distance = 4 m
u =0 m/s
Now, s = ut +1/2at²
= 0×1 + 1/2×8×1²
=4
So, Distance = 4 m
Answered by
13
Initial velocity = 0 m/s
Acceleration = 8m/s ²
time taken = 1 sec
And we have to find distance ,
so distance will be,
S = ut+ ½at ²
S = 0 * 1 + ½ *8*1*1
S = 4 * 1
S = 4
Therefore distance traveled = 4 m
I hope it helps…………….
Acceleration = 8m/s ²
time taken = 1 sec
And we have to find distance ,
so distance will be,
S = ut+ ½at ²
S = 0 * 1 + ½ *8*1*1
S = 4 * 1
S = 4
Therefore distance traveled = 4 m
I hope it helps…………….
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