Question

An object undergoes an acceleration of 8m/sec²starting from rest find distance traveld in 1 sec

Answer 1

Given :

▪ Acceleration of object = 8m/s$^2$

▪ Initial velocity = zero (i.e.,rest)

▪ Time interval = 1s

To Find :

▪ Distance covered by object in the given interval of time.

Concept :

➡ Since, acceleration has said to be constant throughout the entire journey, we can easily apply equation of kinematics to solve this type of questions.

➡ Second equation of kinematics :

$\bigstar\:\underline{\boxed{\bf{\orange{s=ut+\dfrac{1}{2}at^2}}}}$

• s denotes distance
• u denotes initial velocity
• t denotes time
• a denotes acceleration

Calculation :

$:\implies\sf\:s=ut+\dfrac{1}{2}at^2\\ \\ :\implies\sf\:s=(0\times 1)+\dfrac{1}{2}(8\times 1^2)\\ \\ :\implies\sf\:s=0+\dfrac{1}{2}(8)\\ \\ :\implies\underline{\boxed{\bf{\gray{s=4m}}}}$

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✴ First equation of kinematics :

$\bigstar\:\underline{\boxed{\bf{\purple{v=u+at}}}}$

✴ Third equation of kinematics :

$\bigstar\:\underline{\boxed{\bf{\pink{v^2-u^2=2as}}}}$

Answer 2

Aɴꜱᴡᴇʀ

☞ Distance travelled by the motor boat is 4m

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Gɪᴠᴇɴ

✭ Acceleration (a) = 8 m/s²

✭ Initial velocity (u) = 0 m/s

✭ Time (t) = 1 seconds

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Tᴏ ꜰɪɴᴅ

➤ The distance (s) travelled during this time?

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Sᴛᴇᴘꜱ

❍ We can find out answer here with the help of the second law of motion, that is,

$\large{\underline{ \boxed{ \green{ \sf{}s = ut + \frac{1}{2}a {t}^{2} }}}}$

Substituting the given values,

$\large \tt \leadsto{}s = 0 \times 1+ \frac{1}{ \cancel2} \times \cancel8 \times 1\times 1\\ \\ \tt \large \leadsto{}s = 4\times 1 \times 1 \\ \\ \large \tt \pink{\leadsto{}s = 4 \: \sf{}m}$

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