Question

An object undergoes an acceleration of under 8m/s2 starting from rest. Find the distance traveled in 1s?

Answer 1

Answer:

Thus the answer is 4metre.

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Answer 2

Provided that:

• Initial velocity = 0 mps
• Acceleration = 8 mps sq.
• Time = 1 second

To calculate:

• Distance travelled

Solution:

• Distance travelled = 4 m

Using concept:

• Second equation of motion

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{s \: = ut \: + \dfrac{1}{2} \: at^2}}}}}}$

Where, s denotes displacement or distance or height, u denotes initial velocity, t denotes time taken and a denotes acceleration.

Required solution:

$:\implies \sf s \: = ut \: + \dfrac{1}{2} \: at^2 \\ \\ :\implies \sf s = 0(1) + \dfrac{1}{2} \times 8(1)^{2} \\ \\ :\implies \sf s = 0 + \dfrac{1}{2} \times 8(1) \\ \\ :\implies \sf s = 0 + \dfrac{1}{2} \times 8 \\ \\ :\implies \sf s = 0 + 1 \times 4 \\ \\ :\implies \sf s = 0 + 4 \\ \\ :\implies \sf s = 4 \: m \\ \\ :\implies \sf Distance = 4 \: m$