Question

An object undergoes an angular displacement of 60 degree in time 10 second while moving in a circular path. What will be its angular velocity? (60 degree = 3.14/ 3 rad,  angular velocity = angular displacement/ time) ​

Answer 1

Given:

An object undergoes an angular displacement of 60 degree in time 10 second while moving in a circular path.

To find:

Angular velocity ?

Calculation:

First, let's convert angular displacement from degrees to radians.

• 60° = 60 × π/180 rad = π/3 rad.

Now, angular velocity will be angular displacement divided by time:

$\omega = \dfrac{ \theta}{t}$

$\implies \omega = \dfrac{( \dfrac{\pi}{3} )}{10}$

$\implies \omega = \dfrac{\pi}{30} \: rad/s$

$\implies \omega = 0.104 \: rad/s$

So, angular velocity is π/30 or 0.104 rad/s.

Answer 2

Answer:

Given:

An object undergoes an angular displacement of 60 degree in time 10 second while moving in a circular path.

To find:

Angular velocity ?

Calculation:

First, let's convert angular displacement from degrees to radians.

60° = 60 × π/180 rad = π/3 rad.

Now, angular velocity will be angular displacement divided by time:

ω=

$\frac{0}{t}$

⟹ω=

$\frac{ \frac{\pi}{3} }{10}$

⟹ω=

$\frac{\pi}{3}$

⟹ω=0.104rad/s

So, angular velocity is π/30 or 0.104 rad/s.