Question

An object used to sunaunga horizontal surface in such a way that it starts with velocity of 12 metre per secondits velocity decreases at a rate of 0.5 metre per second square find the time taken to come to rest be distance covered by it before coming to rest

Answer 1

Answer:

u=0.5 m/s

a=-0.05 m/s²

v=0

By first equation of motion, we have:

v=u+at

0=0.5-0.05t

0-0.5=-0.05t

-0.5=-0.05t

0.5/0.05=t

50/5=t

10 s=t