An object was at rest.A force of 15 N acts on it for 4 s and then stopped acting.After that the object traverses 54 m in 9 s.What is the mass of the object?
Answers
Given :
Force of 15N acts on an object for 4s.
After that object travelled 54m in 9s.
To Find :
Mass of the object.
Solution :
❒ Force is acting on the object for first 4s it means body has acceleration during this time.
As s per newton's second law of motion;
- F = m × a
Acceleration of object = 15/m
Final velocity of object after first 4s can be calculated by using first equation of kinematics.
➛ v = u + at
- Initial velocity = zero
➛ v = 0 + at
➛ v = 15/m × 4
➛ v = 60/m
After first 4s, object is moving at a constant velocity of 60/m metre per second as force is not acting on the object
➠ velocity = distance/time
➠ 60/m = 54/9
➠ 60/m = 6
➠ m = 60/6
➠ m = 10 kg
Given :
Force of 15N acts on an object for 4s.
After that object travelled 54m in 9s.
To Find :
Mass of the object.
Solution :
❒ Force is acting on the object for first 4s it means body has acceleration during this time.
As s per newton's second law of motion;
F = m × a
Acceleration of object = 15/m
Final velocity of object after first 4s can be calculated by using first equation of kinematics.
➛ v = u + at
Initial velocity = zero
➛ v = 0 + at
➛ v = 15/m × 4
➛ v = 60/m
After first 4s, object is moving at a constant velocity of 60/m metre per second as force is not acting on the object..
➠ velocity = distance/time
➠ 60/m = 54/9
➠ 60/m = 6
➠ m = 60/6
➠ m = 10 kg