Question

An object was dropped from a hill falls with a constant acceleration of 10 m/s^2. Find the speed after 5 seconds it was dropped.
Can we solve it using s = ut+1/2at^2? Why or why not? ​

Answer 1

Answer:

Given that, an object was dropped from a hill with acceleration 10m/s^2

Therefore, we have acceleration here

i.e., a= 10m/s^2

Now we have to find initial velocity u

we have time t = 5s

Substitute the values in equation v = u + at

we know the object was dropped so, the object was not in motion. so initial velocity, u = 0

Explanation:

Therefore,

by substituting the values of u, a and t in equation we get

v = 0 + 10×5

v = 50m/s

Now your question was whether we could solve this question with the equation s = ut + 1/2at^2

No, we can't.

See the question is to find final velocity(v)

We cannot find final velocity with the equation S = ut + 1/2 at^2

Hope it helps.

MARK AS BRAINLIEST