an object was placed on the principle axis of a convex lense 25cm away from the lense a real image 4 time the size of the object was obtained the focal length of lesne
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From the figure,
u=−(25+f)
v=(40+f)
Using lens formula we get
v1 − u1 = f1
f+401 + 25+f1 = f1
65f+2f=1000+65f+f2
f 2=1000
f=31.623cm
∴u=25+31.62=56.62cm
v=40+31.623=71.62cm
m= uv
= −56.62 +71.62
= −1.3
Answer :- -1.3
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