AN OBJECT WEIGHING 10 N IN AIR AND WEIGHS 9.3N IN LIQUID WHAT IS THE BUOYANT FORE OF THAT OBJECT
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Weight in air-Weight in water =Buoyant Force
=>10N-9.3N=0.7N
=>10N-9.3N=0.7N
Answered by
1
weight in air -- weight in water = Buoyant force
=> 10N -- 9.3
=> 0.7 N Answer
=> 10N -- 9.3
=> 0.7 N Answer
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