An object weighing 50 kg is lifted vertically through a height of 10 m. What is the work done?
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Explanation:
(i) W.D by applied force,
w
f
=f
s
=60×5=300J
(ii) change in PE,
PE=mgh=5×9.8×5=245J
(iii) KE=W.D. by resultant force,
=w
g
+w
f
=−245+300=55J
(iv) velocity since KE=55,
V=
5
55×2
=4.69m/s
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