Question

An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. What will be the weight of the liquid displaced by the object?

Answer 1

Heya user.......

Weight in water = 8N
Weight in air = 10N
Weight of liquid displaced = Loss of water = 10N - 8N = 2N

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Answer 2

According to Archimedes principle:
The upward buoyant force that is exerted on a whether fully or partially submerged body immersed in a fluid, is equal to the weight of the fluid that the body displaces and acts in the upward direction at the center of mass of the displaced fluid.
Loss of weight of object = wt of fluid displaced by it
loss of wt = (10-8) N= 2N wt of fluid displaced =2N