Question

An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N . Find the weight of the liquid displaced with the object will be??

Answer 1

Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝

Solution:-

Object weight in air=10N
Object weight in immersed water=8N

then,

Liquid displaced with the object=10N-8N=2N


that's all


@Sujeet

Answer 2

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According to Archimedes principle,
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$\bf \: = > buoyancy \: \: force = weight \: \: of \: \: the \: liquid \: \: dispersed$

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So total weight of object in air = $\bf \: 10 \: \: N$

Total weight of object in water=$\bf \: 8 \: \: N$

So..
Total buoyancy force = 10 - 8 =2N

So..
Total liquid dispersed weighs =$\bf \: 2 \: \: N$

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♥️Hope this is ur required answer♥️

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