An object weight 4 kg and density 4000kg/m3 is completely immersed in water of density 1000kg/m3 find the buoyant force on it?
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Mass of ball m = 4 kg Density of ball ρ = 4000 kg/m3 Volume of the ball V = m/ρ = 4/4000 m3 = 10-3 m3. Buoyant force or upthrust acting on the ball = Volume of water displaced x density of water x acceleration due to gravity = 10-3 m3 x 1000 kg/m3 x 9.8 m/s2 = 9.8 kg. m/s2 = 9.8 N.
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vvipjattin:
dont do it so much compelx just make fbd of q and rethink
it will be 9.8 or 10 ×4 aprx 40 think it again
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Answer:
buoynaty will be =mg
Explanation:
as the block will be in eqiblubrim in water so mg=buoyanty by fbd
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