Question

An object weighting 180N placed on a surface of area 0.4m²,exerts a thrust on the surface equal to

Answer 1

Given:

• Weight of object is 180N.
• Force is exerted over a area of 0.4m².

To Find:-

• The pressure exerted.

Formula Used:

We know that pressure is equal to force by area:

$\large{\underline{\boxed{\red{\sf{\dag Pressure=\dfrac{Force(F)}{Area(A)}}}}}}$

Answer:

Given that a force of 180 Newton is exerted over a area of 0.4 m² .

So , pressure = Force/Area .

= 180N / 0.4 m².

= 1800N / 4 m².

= 450N / m² .

= 450 Pa .

Hence the pressure exerted is 450 Pa.