Question

An object weights 10N at the North pole of earth . in a geostationary satellites distance =7R from the earth , find its


1. True weight and 2. Apparent weight

Answer 1

Heya!
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→ An object weights 10N at the North pole of the earth . In a geostationary satellite , distance is 7R from the centre of the earth . Find its -


(i) True Weight
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→ We have , mg = 10N

★True weight of body in Geostationary is =

→ Ws = mg'

$= > ws =mg \: ( \frac{r}{r + h} ) {}^{2} \\ \\ = > ws = mg \: ( \frac{r}{r + 6r} ) {}^{2} \\ \\ = > ws = mg \times \frac{1}{49}$

[ For h = 7R - R = 6R and then squaring equation ]

★Now mg = 10 N


•°• Ws → 10 / 49


↪The true weight of the body is 0.2 N

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(ii) Apparent weight
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=> g' is the acceleration due to gravity . Then apparent weight Wap. = m ( g' - a )

Now , the body is under Free Fall so a = g'


°•° Wapp. = m ( g' - g' )

=> 0


↪The apparent weight of the body is 0.
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Answer 2

Here's the answer :


True weight = mg / R / (R + 6R )²


= 10 / 59


Apparent weight = g' ( a - a ) = 0