an object when falls from rest possess 400J of kinetic energy at the end of 2sec.calculate the mass of the object
Answers
Answered by
18
Given:
Kinetic energy=K.E=400J
time=t=2sec
u=0m/s
mass=m=?
Let us find out Velocity at the end of 2sec:
From first equation of motion:
V=u+gt
V=0+10x 2 [∵g=10m/s²]
=20 m/s
K.E=mV²/2
m=2XK.E/V²
⇒2x400/20x20
⇒2kg
∴ Mass of the object is 2kg
Kinetic energy=K.E=400J
time=t=2sec
u=0m/s
mass=m=?
Let us find out Velocity at the end of 2sec:
From first equation of motion:
V=u+gt
V=0+10x 2 [∵g=10m/s²]
=20 m/s
K.E=mV²/2
m=2XK.E/V²
⇒2x400/20x20
⇒2kg
∴ Mass of the object is 2kg
Answered by
0
Answer:
Given:
Kinetic energy=K.E=400J
time=t=2sec
u=0m/s
mass=m=?
Let us find out Velocity at the end of 2sec:
From first equation of motion:
V=u+gt
V=0+10x 2 [∵g=10m/s²]
=20 m/s
K.E=mV²/2
m=2XK.E/V²
⇒2x400/20x20
⇒2kg
∴ Mass of the object is 2kg
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