Question

An object which is thrown or projected into the air, subject to only the acceleration of gravity is
called a projectile, and its path is called its trajectory. This curved path was shown by Galileo to
be a parabola. Parabola is represented by a polynomial. If the polynomial to represent the
distance covered is $p (t) = -5tx^{2} +40t+1.2$

Find the height of projectile 4 seconds after it is launched

Answer 1

Answer:

81.2

Step-by-step explanation:

We replace t with 4

Answer 2

Step-by-step explanation:

To determine the height of a projectile 4 seconds after it is launched, we can use the equations for the vertical and horizontal motion of a projectile. These equations take into account the initial velocity, the acceleration due to gravity, and the time elapsed. The vertical motion of a projectile is given by the equation:

h = v0t - 1/2gt^2

where h is the height, v0 is the initial velocity, t is the time elapsed, and g is the acceleration due to gravity (approximately 9.8 m/s^2 on the surface of the earth). The horizontal motion is given by the equation:

x = v0t

where x is the horizontal distance traveled. To find the height of the projectile 4 seconds after it was launched, we need to substitute t = 4 into both equations and solve for h. The value of v0 will depend on the initial conditions of the projectile and the direction it was launched.

Given the above information, the height of the projectile 4 seconds after it was launched can be determined by solving the equations for vertical and horizontal motion, taking into account the initial velocity, time elapsed, and acceleration due to gravity.

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