an object which placed at the 10cm from a convex mirror of focal length 15cm find position and image .
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1
Answer:
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Focal length (f) = 15 cm
Distance of object from the convex mirror (u) = 10 cm
Image distance (v) = ?
1/v - 1/u = 1/f
1/v - 1/10 = 1/15
1/v = 1/5 + 1/10
1/v = 2 + 3 / 30
1/v = 5/30
1/v = 1/6
v = 6 cm
Image distance = 6 cm
Image distance is in positive, thus the image is formed behind the mirror, thus it's VIRTUAL and ERECT.
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Answered by
0
Answer:
Focal length (f) = 15 cm
Distance of object from the convex mirror (u) = 10 cm
Image distance (v) = ?
1/v - 1/u = 1/f
1/v - 1/10 = 1/15
1/v = 1/5 + 1/10
1/v = 2 + 3 / 30
1/v = 5/30
1/v = 1/6
v = 6 cm
Image distance = 6 cm
Image distance is in positive, thus the image is formed behind the mirror, thus it's VIRTUAL and ERECT.
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