an object with a mass 10 kg moves at a constant velocity of 10 metre per second a constant force then acts for 4 second on the object giving it a speed 2 metre per second opposite direction .the acceleration produced is
laxmikant6:
plss solve
Answers
Answered by
9
Hi ...dear...
here is your answer....
Change in velocity
-2-10=-12
Time required is 4 seconds
a=deltav/t
=-12/4
=-3 m/s²..... hope it helped you...!!
here is your answer....
Change in velocity
-2-10=-12
Time required is 4 seconds
a=deltav/t
=-12/4
=-3 m/s²..... hope it helped you...!!
Answered by
0
Answer:
Initial Velocity (u) = 10m/s
Final Velocity (v) = -2m/s
Now, we need to calculate the retardation because there is decreasing velocity
retardation = \frac{v - u}{t} \\ = \frac{ - 2 - 10}{4} \\ = \frac{ - 12m \: s ^{ - 1} }{4s} = {-3 m \: s}^{ - 2}
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