Question

An object with a mass 10kg moves at a constant force thean acts for 4 second on the object and gives it aspreed of 2m/sec . in opposite direction . the acceleration produced in it, is

Answer 1

M=10kg
T=4s
V=2m/s
F=momentum/time
F=MV/T
=10×2/4
=-5N nagative sign because it act in a object in opposite direction
F=Ma
a=F/M
=-5/10=-0.5m/s^2