Question

An object with a mass of 0.5kg is undergoing simple harmonic motion on the end of a horizontal spring with a spring constant k=400N/m.when the object is 0.012m from its equilibrium postion ,it is onsetved to have a speed of 0.3m/s.calculate the amplitude of the motion?​

Answer 1

Answer:

all I help you? change into the assertive sentence

Answer 2

Answer:

A = 0.016 m

Explanation:

v=ω √A²-x²

0.3=√400/0.5 (√A²-0.012²)

A= 0.016 m