An object with a mass of 1.5 kg changes its velocity from +15 m/s to +22 m/s during a time interval of 3.5 seconds. What impulse was delivered to the object?
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Answered by
3
Impulse= mv-mu
so, here mv= 1.5×22
and mu= 1.5×15
therefore, I = m(v-u)
= 1.5(22-15)
= 1.5 × 7
= 10.5 N
so, here mv= 1.5×22
and mu= 1.5×15
therefore, I = m(v-u)
= 1.5(22-15)
= 1.5 × 7
= 10.5 N
TheGod:
(v-u)/t
Answered by
2
The impulse which is delivered to an object is 10.5 N
Given:
Mass = 1.5 kg
Velocity changes from “+15 m/s to +22 m/s”
Time interval = 3.5 sec
To Find:
Impulse delivered to object.
Solution:
The impulse is a one which causes something to happen or to happen quickly. The Impulse is an integral of force over the “time interval”. Impulse is a vector quantity.
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