Physics, asked by bigjohn9899, 1 year ago

An object with a mass of 1.5 kg changes its velocity from +15 m/s to +22 m/s during a time interval of 3.5 seconds. What impulse was delivered to the object?

Answers

Answered by TheGod
3
Impulse= mv-mu
so, here mv= 1.5×22
and mu= 1.5×15
therefore, I = m(v-u)
= 1.5(22-15)
= 1.5 × 7
= 10.5 N

TheGod: (v-u)/t
TheGod: =2
TheGod: therefore
TheGod: I=
TheGod: I =
TheGod: F×t
TheGod: which is
TheGod: ma×t
TheGod: 1.5 ×2×3.5
TheGod: = 10.5 N
Answered by skyfall63
2

The impulse which is delivered to an object is 10.5 N

Given:

Mass = 1.5  kg

Velocity changes from “+15 m/s to +22 m/s”

Time interval = 3.5 sec

To Find:

Impulse delivered to object.

Solution:

\text{Impulse} = \text{mv} - \text{mu}

I=m(v-u)

I=1.5(22-15)

I=1.5 \times 7

I=10.5 \ N

The impulse is a one which causes something to happen or to happen quickly. The Impulse is an integral of force over the “time interval”. Impulse is a vector quantity.  

Similar questions