Question

an object with a mass of 10kg moves at a constant velocity of 10m/s. A constant force then acts for 4 sec on the object and gives it a speed of 2m/sec in opposite direction. The acceleration produced in it is,

Answer 1

The acceleration produced is $\bold{3\ \mathrm{m} / \mathrm{s}^{2}}$

Solution:

The ‘formula for acceleration’ is $a=\frac{|v-u|}{t}$

Here, a is the acceleration, v is the final velocity, u is the initial velocity and t is time.

The given data’s are as such

v = -2 m/s

u = 10 m/s

t = 4 s

Hence, $a=\frac{|-2-10|}{4}=\frac{12}{4}=3\ m / s^{2}$.

Thus, the acceleration is $3\ \mathrm{m} / \mathrm{s}^{2}$.

Acceleration is a ‘vector quantity’ defined as ‘the rate’ at which “an object changes its velocity”. An ‘object is accelerating’ if it is ‘changing its velocity’.

Answer 2

Answer:

the answer 3m/s^2

Explanation: