Question

An object with a mass of 2300 g has a force of 6.2 newtons applied to it. What is the reulting acceleration of the object

Answer 1

Given:-

The mass of an object is 2300 g.

Force applied to it = 6.2 N

To find:-

The resulting acceleration of the object.

Solution:-

We know,

$\displaystyle{F=ma}$

F = 6.2 N

m = 2300 g = 2300/1000 kg = 2.3 kg

a = F/m

⇒a = 6.2/2.3

$\boxed{\implies a = 2.69\ m/s^2}$

So, the resulting acceleration of the object is 2.69 m/s².

Answer 2

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QUESTION :

An object with a mass of 2300 g has a force of 6.2 newtons applied to it.

What is the reulting acceleration of the object ?

SOLUTION :

We know the following formula , which is derived from the Newton's laws of motion :

F = M × A

Where :

F is the external force applied on the object.

M is the mass of the object.

A is the acceleration of the object .

In this above Question, the following information is given :

An object with a mass of 2300 g has a force of 6.2 newtons applied to it.

Substituting these values into the above formula, we can form the following equation , which is stated below.

6.2 N =2.3 kg × A

=> A = Force / Mass

=> A = { 6.2 /2.3 } m / s ^ 2

=> a = 2.69 m / s ^ 2

ANSWER :

The resulting acceleration of the object is 2.69 m / s ^ 2.

ADDITIONAL INFORMATION

Acceleration , and Force are vector quantities.

Mass is a scalar quantity.

The dimension of Acceleration is L×T^ { -2 }

The dimension of force is M × L × T ^ { -2 }