Question

An object with a net positive charge of 2×10^-12 coulomb contains 1.5×10^7 protons. Find the no. Of electrons present in it

Answer 1

We have to find the number of electrons present in an object which has net positive charge 2 × 10¯¹² C contains 1.5 × 10^7 protons.

To find : magnitude of charge on proton equals to charge on electron but first one is positive and the other one is negative.

Charge on electron = charge on proton = 1.6 × 10^-19 C

here no of protons = 1.5 × 10^7

so, total charge of protons = 1.6 × 10^-19 × 1.5 × 10^7 = 2.4 × 10¯¹² C

Now, remaining charge of object = 2 × 10¯¹² C - 2.4 × 10¯¹² = -0.4 × 10¯¹² C

Now no of electrons = remaining charge/charge on electrons

= -0.4 × 10¯¹²C/-1.6 × 10^-19

= 1/4 × 10^7

= 2.5 × 10^6

Therefore the number of electrons is 2.5 × 10⁶

Answer 2

Answer:

eertuoopkhgbg tf f rd rd 4d 6gb6gb6tv5d 4ex4rdgt6gyg6g6y