an object with an initial velocity of 20 m/s accelerates uniformly at 5 m/s raised to the second power for 10 seconds what is the final velocity of the object
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Answer:
Explanation:
Uniformly suggests uniform acceleration. That acceleration is change of speed over time. (20–10)/5 = 2m/s/s
Distance =initial velocity * time + (acceleration * time^2) / 2
Distance = 10 *5 + (2*5^2)/2 = 75m
There are other easier (“geometrical approaches”)
Simply use mean speed theorem. As the acceleation is uniform, distance travelled increases identically to its increase at average mean speed. Therefore
Distance = time * average speed = time * (initial speed + final speed) / 2
Distance = 5 * (10 + 20)/2 = 5 * 15 = 75m
vishal
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