Question

An object with initial velocity 2m/s is being accelerated with a constant acceleration of 3m/s in the same
direction as the velocity.Find out distance travelled by the object in first five seconds.​

Answer 1

Acceleration =v-u/t

=3-2/5

=1m/5s²

S=ut+½at²

=2×5+½×⅕×5×5

=10+½×5

=10+5/2

=(20+5)/2

=25/2 m

Therefore distance travelled=12.5 m

Answer 2

hope it helps.......

........