Question

an object with initial velocity 4m/s got its velocity tobe 40m/s after a time of 5 seconds. Find the force applied if mass of the object is 2 kg​

Answer 1

Given:-

→ Initial velocity of the object = 4 m/s

→ Final velocity = 40 m/s

→ Mass of the object = 2 kg

→ Time taken = 5 seconds

To find:-

→ Magnitude of force applied.

Solution:-

By Newton's 2nd law of motion, we know that :-

F = m(v - u)/t

Where :-

• F is the force.

• m is mass of the object.

• v is final velocity.

• u is initial velocity.

• t is time taken.

Substituting values, we get :-

⇒ F = 2(40 - 4)/5

⇒ F = 2(36)/5

⇒ F = 72/5

⇒ F = 14.4 N

Thus, the magnitude of force applied is 14.4 N .

Answer 2

Given : Initial Velocity [ u ] of the object is 4 m/s , Final Velocity of the ball [ v ] 40 m /s , Total Time taken is [ t ] is 5 seconds & The mass [ m ] of the ball is 2 kg .

Exigency To Find : Force Applied [ F ] .

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Given that ,

• Initial Velocity [ u ] of the object is 4 m/s
• Final Velocity [ v ] of the object is 40 m /s
• Total Time taken [ t ] is is 5 seconds
• The mass [ m ] of the ball is 2 kg .

Now ,

$\dag\:\:\sf{ As,\:We\:know\:that\::}\\\\ \qquad\maltese\:\:\bf From \: Second\:Law's \:of \:Newton \::$

$\qquad \dag\:\:\bigg\lgroup \sf{ F = \dfrac{ m ( v- u ) }{t} }\bigg\rgroup$

⠀⠀⠀⠀⠀Here F is Applied force , m is the mass , v is the Final velocity, u is the Initial velocity & t is the total time taken.

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ m ( v- u ) }{t} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 2 ( 40 - 4 ) }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 2 ( 36 ) }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 2 \times 36 }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 72 }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \cancel {\dfrac{ 72 }{5}} \:$

$\qquad :\implies \bf Force \: Applied\: = 14.4 \:$

$\qquad:\implies \frak{\underline{\purple{\: Force \: Applied\: = 14.4 \: N \:}} }\:\:\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:The\:force\: Applied \:is\:\bf{14.4 \: N}}}}$

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