Question

an object with initial velocity 4m/s got its velocity tobe 40m/s after a time of 5 seconds. Find the force applied if mass of the object is 2 kg​

Answer 1

Answer:

14.4kgm/s²

Step-by-step explanation:

here, u=4m/s

v=40m/s

t=5s

a= v-u/t

a=40m/s-4m/s/5s

=36m/s/5s

=7.2m/s²

Now,

f=m×a

=2kg×7.2m/s²

=14.4kgm/s²

hope it helps