Question

an object with initial velocity 4m/s got its velocity tobe 40m/s after a time of 5 seconds. Find the force applied if mass of the object is 2 kg​

Answer 1

Given that ,

Initial Velocity [ u ] of the object is 4 m/s.

Final Velocity [ v ] of the object is 40 m /s.

Total Time taken [ t ] is is 5 seconds.

The mass [ m ] of the ball is 2 kg .

Now ,

$\dag\:\:\sf{ As,\:We\:know\:that\::}\\\\ \qquad\maltese\:\:\bf From \: Second\:Law's \:of \:Newton \::$

$\qquad \dag\:\:\bigg\lgroup \sf{ F = \dfrac{ m ( v- u ) }{t} }\bigg\rgroup$

⠀⠀⠀⠀⠀Here F is Applied force , m is the mass, v is the Final velocity, u is the Initial velocity & t is the total time taken.

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ m ( v- u ) }{t} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 2 ( 40 - 4 ) }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 2 ( 36 ) }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 2 \times 36 }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \dfrac{ 72 }{5} \:$

$\qquad :\implies \sf Force \: Applied\: = \cancel {\dfrac{ 72 }{5}} \:$

$\qquad :\implies \bf Force \: Applied\: = 14.4 \:$

$\qquad:\implies \frak{\underline{\pink{\: Force \: Applied\: = 14.4 \: N \:}} }\:\:\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:The\:force\: Applied \:is\:\bf{14.4 \: N}}}}$

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