Question

An objects is moving along x-axis in such a way that displacement is given by x=30plus 20t squire where x is in metres and t is in sec [a] find the velocity and acceleration of objects. [b] what are the intial position and the velocity of the objects question mark

Answer 1

Answer:

a) v = dx/dt = 40t

a = dv/dt = 40 (constant)

b) x(0) = 30 metres

v(0) = 0 m/s

Explanation:

x = 30 + 20t^2

v = dx/dt = 40t

a = dv/dt = 40 (constant)

initial position at t=0,

x(0) = 30 metres

v(0) = 0 m/s

Answer 2

Answer:

here is your answer. .....