Question

an objecy moving with a velocity 10m/s and attains a maximum speed 72kmph in 45 sec calculate the distance traveled by an object​

Answer 1

Answer:

By using the equation of motion

v=u+at

By substituting the given values in the above equation

15=6+105t

Then the time is0.0857sec

The distance covered is given as

S=ut+

2

1

at

2

S=6×0.0857+

2

1

×105×(0.0857)

2

S=0.514+0.385

The distance covered is0.899m