Question

An objecy start moving at the rate of
6m/s.if it is accelerated uniformly at
the rate of 1.2 m/s2 then calculate.
1. the time after which is velocity becomes
18 m/s
2. Distance travelled in 4 second.​

Answer 1

Answer:

Given,

Intial velocity = 6m/s

Rate of Accⁿ = 1.2m/s²

Now,

In case 1

Final velocity = 18 m/s

Time = ?

By using 1st eqn of motion

v = u + at

18 = 6 + 1.2t

12 = 1.2t

t = 12/1.2

t = 10s

In case 2

Time = 4s

By using 2nd eqn of motion

s = ut + 1/2at²

s = 24 + 1/2 × (1.2) × 16

s = 24 + 9.6

s = 33.6m

I was typing just after waking up from sleep please forgive if there is any error