Question

an observed 1.6m tall is 30.5m away from the tower the angle of e from top of tpwer is 45 degeree what is height of the tower

Answer 1

Answer:

32.1 m tall

Let the hight of the tower be AC and point from the observer to foot of the tower be BC

Now,

tan45°=AC/BC

1=AC/BC

1=AC/30.5

AC=30.5 + hight of the observer i.e 1.6m

AC=30.5+1.6

AC =32.1m

therefore hight of the tower is 32.1m

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