Question

an observer 1.5 m tall is 28.5 M away from a tower 30 M high the angle of elevation of the top of the tower from his eyes

Answer 1

here is ur answer in the attachment above

Answer 2

Answer:

tan(θ)=

adjacent

opposite

Find the angle of elevation:

\tan(\theta) =\dfrac{\text{30 - 1.5}}{\text{28.5}}tan(θ)=

28.5

30 - 1.5

\tan(\theta) =\dfrac{\text{28.5}}{\text{28.5}}tan(θ)=

28.5

28.5

\tan(\theta) = 1tan(θ)=1

\theta = tan^{-1}(1)θ=tan

−1

(1)

\theta = 45 \textdegreeθ=45\textdegree

Answer: The angle of elevation is 45°