Question

. An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high.
Determine the angle of elevation of the top of the tower from the eye of the
observer.​

Answer 1

Answer:

h of tower = 22m

distance between tower and man =20.5m

height of man=1.5m

So angle of elevation will be formed from eyes of the observer = 22-1.5=20.5

Now,

tan theta=p/b

20.5/20.5=1

tan theta =tan 45 °

theta =45°