an observer 1.5m tall is 20√3m away from chimney. the angle of elevation of the top of the chimney from his eyes is 30° find the height of the chimney.
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Answer:
From the figure:
Let AB be the position of the observer and CD be the height of the chimney h meters.
AC=BE=30 m
From ΔBED
tan60
o
=
BE
DE
⇒
3
=
BE
DE
⇒ h−1.5=30
3
⇒ h=53.4 (approx)
∴ Height of the chimney is 53.4 m
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